Optimal. Leaf size=195 \[ \frac{b \left (15 b^2-52 a c\right ) \sqrt{a+b x^2+c x^4}}{8 a^3 x^2 \left (b^2-4 a c\right )}-\frac{\left (5 b^2-12 a c\right ) \sqrt{a+b x^2+c x^4}}{4 a^2 x^4 \left (b^2-4 a c\right )}-\frac{3 \left (5 b^2-4 a c\right ) \tanh ^{-1}\left (\frac{2 a+b x^2}{2 \sqrt{a} \sqrt{a+b x^2+c x^4}}\right )}{16 a^{7/2}}+\frac{-2 a c+b^2+b c x^2}{a x^4 \left (b^2-4 a c\right ) \sqrt{a+b x^2+c x^4}} \]
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Rubi [A] time = 0.211298, antiderivative size = 195, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.3, Rules used = {1114, 740, 834, 806, 724, 206} \[ \frac{b \left (15 b^2-52 a c\right ) \sqrt{a+b x^2+c x^4}}{8 a^3 x^2 \left (b^2-4 a c\right )}-\frac{\left (5 b^2-12 a c\right ) \sqrt{a+b x^2+c x^4}}{4 a^2 x^4 \left (b^2-4 a c\right )}-\frac{3 \left (5 b^2-4 a c\right ) \tanh ^{-1}\left (\frac{2 a+b x^2}{2 \sqrt{a} \sqrt{a+b x^2+c x^4}}\right )}{16 a^{7/2}}+\frac{-2 a c+b^2+b c x^2}{a x^4 \left (b^2-4 a c\right ) \sqrt{a+b x^2+c x^4}} \]
Antiderivative was successfully verified.
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Rule 1114
Rule 740
Rule 834
Rule 806
Rule 724
Rule 206
Rubi steps
\begin{align*} \int \frac{1}{x^5 \left (a+b x^2+c x^4\right )^{3/2}} \, dx &=\frac{1}{2} \operatorname{Subst}\left (\int \frac{1}{x^3 \left (a+b x+c x^2\right )^{3/2}} \, dx,x,x^2\right )\\ &=\frac{b^2-2 a c+b c x^2}{a \left (b^2-4 a c\right ) x^4 \sqrt{a+b x^2+c x^4}}-\frac{\operatorname{Subst}\left (\int \frac{\frac{1}{2} \left (-5 b^2+12 a c\right )-2 b c x}{x^3 \sqrt{a+b x+c x^2}} \, dx,x,x^2\right )}{a \left (b^2-4 a c\right )}\\ &=\frac{b^2-2 a c+b c x^2}{a \left (b^2-4 a c\right ) x^4 \sqrt{a+b x^2+c x^4}}-\frac{\left (5 b^2-12 a c\right ) \sqrt{a+b x^2+c x^4}}{4 a^2 \left (b^2-4 a c\right ) x^4}+\frac{\operatorname{Subst}\left (\int \frac{-\frac{1}{4} b \left (15 b^2-52 a c\right )-\frac{1}{2} c \left (5 b^2-12 a c\right ) x}{x^2 \sqrt{a+b x+c x^2}} \, dx,x,x^2\right )}{2 a^2 \left (b^2-4 a c\right )}\\ &=\frac{b^2-2 a c+b c x^2}{a \left (b^2-4 a c\right ) x^4 \sqrt{a+b x^2+c x^4}}-\frac{\left (5 b^2-12 a c\right ) \sqrt{a+b x^2+c x^4}}{4 a^2 \left (b^2-4 a c\right ) x^4}+\frac{b \left (15 b^2-52 a c\right ) \sqrt{a+b x^2+c x^4}}{8 a^3 \left (b^2-4 a c\right ) x^2}+\frac{\left (3 \left (5 b^2-4 a c\right )\right ) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{a+b x+c x^2}} \, dx,x,x^2\right )}{16 a^3}\\ &=\frac{b^2-2 a c+b c x^2}{a \left (b^2-4 a c\right ) x^4 \sqrt{a+b x^2+c x^4}}-\frac{\left (5 b^2-12 a c\right ) \sqrt{a+b x^2+c x^4}}{4 a^2 \left (b^2-4 a c\right ) x^4}+\frac{b \left (15 b^2-52 a c\right ) \sqrt{a+b x^2+c x^4}}{8 a^3 \left (b^2-4 a c\right ) x^2}-\frac{\left (3 \left (5 b^2-4 a c\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 a-x^2} \, dx,x,\frac{2 a+b x^2}{\sqrt{a+b x^2+c x^4}}\right )}{8 a^3}\\ &=\frac{b^2-2 a c+b c x^2}{a \left (b^2-4 a c\right ) x^4 \sqrt{a+b x^2+c x^4}}-\frac{\left (5 b^2-12 a c\right ) \sqrt{a+b x^2+c x^4}}{4 a^2 \left (b^2-4 a c\right ) x^4}+\frac{b \left (15 b^2-52 a c\right ) \sqrt{a+b x^2+c x^4}}{8 a^3 \left (b^2-4 a c\right ) x^2}-\frac{3 \left (5 b^2-4 a c\right ) \tanh ^{-1}\left (\frac{2 a+b x^2}{2 \sqrt{a} \sqrt{a+b x^2+c x^4}}\right )}{16 a^{7/2}}\\ \end{align*}
Mathematica [A] time = 0.130459, size = 179, normalized size = 0.92 \[ \frac{\frac{2 \sqrt{a} \left (2 a^2 \left (b^2+10 b c x^2-12 c^2 x^4\right )-8 a^3 c+a b x^2 \left (-5 b^2+62 b c x^2+52 c^2 x^4\right )-15 b^3 x^4 \left (b+c x^2\right )\right )}{x^4 \sqrt{a+b x^2+c x^4}}+3 \left (16 a^2 c^2-24 a b^2 c+5 b^4\right ) \tanh ^{-1}\left (\frac{2 a+b x^2}{2 \sqrt{a} \sqrt{a+b x^2+c x^4}}\right )}{16 a^{7/2} \left (4 a c-b^2\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.173, size = 314, normalized size = 1.6 \begin{align*} -{\frac{1}{4\,a{x}^{4}}{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}+{\frac{5\,b}{8\,{a}^{2}{x}^{2}}{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}+{\frac{15\,{b}^{2}}{16\,{a}^{3}}{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}-{\frac{15\,{b}^{3}{x}^{2}c}{8\,{a}^{3} \left ( 4\,ac-{b}^{2} \right ) }{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}-{\frac{15\,{b}^{4}}{16\,{a}^{3} \left ( 4\,ac-{b}^{2} \right ) }{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}-{\frac{15\,{b}^{2}}{16}\ln \left ({\frac{1}{{x}^{2}} \left ( 2\,a+b{x}^{2}+2\,\sqrt{a}\sqrt{c{x}^{4}+b{x}^{2}+a} \right ) } \right ){a}^{-{\frac{7}{2}}}}+{\frac{13\,b{c}^{2}{x}^{2}}{2\,{a}^{2} \left ( 4\,ac-{b}^{2} \right ) }{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}+{\frac{13\,{b}^{2}c}{4\,{a}^{2} \left ( 4\,ac-{b}^{2} \right ) }{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}-{\frac{3\,c}{4\,{a}^{2}}{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}+{\frac{3\,c}{4}\ln \left ({\frac{1}{{x}^{2}} \left ( 2\,a+b{x}^{2}+2\,\sqrt{a}\sqrt{c{x}^{4}+b{x}^{2}+a} \right ) } \right ){a}^{-{\frac{5}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.61057, size = 1314, normalized size = 6.74 \begin{align*} \left [-\frac{3 \,{\left ({\left (5 \, b^{4} c - 24 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{8} +{\left (5 \, b^{5} - 24 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} x^{6} +{\left (5 \, a b^{4} - 24 \, a^{2} b^{2} c + 16 \, a^{3} c^{2}\right )} x^{4}\right )} \sqrt{a} \log \left (-\frac{{\left (b^{2} + 4 \, a c\right )} x^{4} + 8 \, a b x^{2} + 4 \, \sqrt{c x^{4} + b x^{2} + a}{\left (b x^{2} + 2 \, a\right )} \sqrt{a} + 8 \, a^{2}}{x^{4}}\right ) - 4 \,{\left ({\left (15 \, a b^{3} c - 52 \, a^{2} b c^{2}\right )} x^{6} - 2 \, a^{3} b^{2} + 8 \, a^{4} c +{\left (15 \, a b^{4} - 62 \, a^{2} b^{2} c + 24 \, a^{3} c^{2}\right )} x^{4} + 5 \,{\left (a^{2} b^{3} - 4 \, a^{3} b c\right )} x^{2}\right )} \sqrt{c x^{4} + b x^{2} + a}}{32 \,{\left ({\left (a^{4} b^{2} c - 4 \, a^{5} c^{2}\right )} x^{8} +{\left (a^{4} b^{3} - 4 \, a^{5} b c\right )} x^{6} +{\left (a^{5} b^{2} - 4 \, a^{6} c\right )} x^{4}\right )}}, \frac{3 \,{\left ({\left (5 \, b^{4} c - 24 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{8} +{\left (5 \, b^{5} - 24 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} x^{6} +{\left (5 \, a b^{4} - 24 \, a^{2} b^{2} c + 16 \, a^{3} c^{2}\right )} x^{4}\right )} \sqrt{-a} \arctan \left (\frac{\sqrt{c x^{4} + b x^{2} + a}{\left (b x^{2} + 2 \, a\right )} \sqrt{-a}}{2 \,{\left (a c x^{4} + a b x^{2} + a^{2}\right )}}\right ) + 2 \,{\left ({\left (15 \, a b^{3} c - 52 \, a^{2} b c^{2}\right )} x^{6} - 2 \, a^{3} b^{2} + 8 \, a^{4} c +{\left (15 \, a b^{4} - 62 \, a^{2} b^{2} c + 24 \, a^{3} c^{2}\right )} x^{4} + 5 \,{\left (a^{2} b^{3} - 4 \, a^{3} b c\right )} x^{2}\right )} \sqrt{c x^{4} + b x^{2} + a}}{16 \,{\left ({\left (a^{4} b^{2} c - 4 \, a^{5} c^{2}\right )} x^{8} +{\left (a^{4} b^{3} - 4 \, a^{5} b c\right )} x^{6} +{\left (a^{5} b^{2} - 4 \, a^{6} c\right )} x^{4}\right )}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{x^{5} \left (a + b x^{2} + c x^{4}\right )^{\frac{3}{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (c x^{4} + b x^{2} + a\right )}^{\frac{3}{2}} x^{5}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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